Which of the following is the total number of whole boxes that measure 2.4 ft * 2.4 ft * 2.4 ft that can be stored in a room that measures 18 ft * 18 ft * 18 ft, if the size of the boxes cannot be altered?
A. 125
B. 92
C. 422
D. 400
The number of boxes is determined by finding the volume of the room divided by the volume of the box.
Number of boxes
The number of boxes that can be stored in the room is about 422.
Therefore, the Correct Answer is C.
More Questions on TEAS 7 Math
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Q #1: -1/3, -0.6, -1.5, -7/3. Of the numbers listed above, which number is the greatest?
A. -0.6
B. -7/3
C. -1/3
D. -1.5
Answer Explanation
To find the greatest value, we need to have uniform numbers. That is, all numbers must be in fraction for easy comparison. Therefore, we convert -0.6, and -1.5 into fractions as follows. For purposes of easy computation, we do not simplify the resulting fractions.
-0.6=-6/10
-1.5=-15/10
Now, the resulting fractions are -1/3, -6/10, -15/10, and -7/3. The greatest value is found by finding the LCM of the denominators and multiplying with each fraction. The LCM of 3 and 10 is 30. Then,
-1/3*30=-10
-6/10*30=-18
-15/10*30=-45
-7/3*30=-70
Based on the obtained values, -10 is the greatest value and -70 the least value. Therefore, -1/3 is the greatest of all the four options.
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Q #2: Which of the following is the total number of whole boxes that measure 2.4 ft * 2.4 ft * 2.4 ft that can be stored in a room that measures 18 ft * 18 ft * 18 ft, if the size of the boxes cannot be altered?
A. 125
B. 92
C. 422
D. 400
Answer Explanation
The number of boxes is determined by finding the volume of the room divided by the volume of the box.
Number of boxes
The number of boxes that can be stored in the room is about 422.
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Q #3: Which of the following is the weight of the cargo in a truck if 3/5 of the cargo weighs 615 pounds (lb)?
A. 1025 lb
B. 1320 lb
C. 1548 lb
D. 788 lb
Answer Explanation
In this problem, we assume the truck carry a whole cargo to carry. Thus, total weight is found by dividing 615 lb by 3/5. Thus,
We change the division sign to product and multiply 615 by reciprocal of 3/5. Then,
(615 * frac{5}{3} = 1025 lb)
The weight of the cargo in the truck will be 1025 lb.
