Which of the following is the total number of whole boxes that measure 2 ft * 2 ft * 2 ft that can be stored in a room that measures 9 ft * 9 ft * 9 ft, if the size of the boxes cannot not be altered?
A. 125
B. 64
C. 18
D. 92
Number of boxes in the room is equal to the volume of the room divided by the volume of one box
Volume of the room=9 ft*9 ft*9 ft= 729 ft3
Volume of one box = 2 ft* 2 ft * 2 ft= 8 ft3
Number of boxes= 729 ft3/ 8 ft3= 91.125 boxes
Thus, the room can store 91.125 boxes, which is about 92 boxes
Therefore, the Correct Answer is D.
More Questions on TEAS 7 Math
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Q #1: A recipe calls for 2.5 teaspoons of vanilla. 1 teaspoon equals approximately 4.93 mL. Which of the following is the correct amount of vanilla in mL?
A. 5.33 mL
B. 7.43 mL
C. 12.325 mL
D. 0.507 mL
Answer Explanation
Use the relation 1 teaspoon=4.93 mL to change 2.5 teaspoons to mL. Using the dimension analysis, the amount in mL is found as:
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Q #2: Which of the following is the total number of whole boxes that measure 2 ft * 2 ft * 2 ft that can be stored in a room that measures 9 ft * 9 ft * 9 ft, if the size of the boxes cannot not be altered?
A. 125
B. 64
C. 18
D. 92
Answer Explanation
Number of boxes in the room is equal to the volume of the room divided by the volume of one box
Volume of the room=9 ft*9 ft*9 ft= 729 ft3
Volume of one box = 2 ft* 2 ft * 2 ft= 8 ft3
Number of boxes= 729 ft3/ 8 ft3= 91.125 boxes
Thus, the room can store 91.125 boxes, which is about 92 boxes
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Q #3: A new physician saw 841 clients during the first year of practice and 1072 clients during the second year of the practice. Which of the following represents the approximate percentage increase in the client volume?
A. 22%
B. 27%
C. 127%
D. 78%
Answer Explanation
Change in weight of client=new -old=1072-841= 231
Percent change=change/old*100%=231/841*100%=27.47%
The percentage change increase is about 27%
