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What is the typical way a solid would turn to a liquid and then to a gas?

A. Vaporizing, then melting

B. Melting, then freezing

C. Vaporizing, then freezing

D. Melting, then vaporizing

Answer Explanation:

A solid turns into a liquid by melting, and a liquid turns into gas by vaporization.

Therefore, the Correct Answer is D.

More Questions on TEAS 7 Science

  • Q #1: What is most likely the pH of a solution containing many hydroxide ions (OH-) and few hydrogen ions(H+)

    A. 2

    B. 6

    C. 7

    D. 9

    Answer Explanation

    A solution that contains more hydroxide ions than hydrogen ions is a base, and bases have a pH greater than 7, so the only possible answer is choice D. 9.

  • Q #2: What type of mutation is represented by the following sequence? Original: 123456 Mutated: 154326

    A. Breakage

    B. Deletion

    C. Insertion

    D. Inversion

    Answer Explanation

    An inversion mutation is represented in the sequence 1 5 4 3 2 6. An inversion error is a type of mutation where an entire sequence of DNA is reversed. In this case, 2 3 4 5 has been reversed to 5 4 3 2.

    Breakage, choice A, in a gene can mess up its function entirely or lead to a translocation of genetic information. Choice B, deletion, is when a section of DNA is omitted or lost.

    Choice C, Insertion, is when an extra base pair is added to a DNA sequence. Deletions and insertions can lead to a frameshift effect where entire sequences are thrown off because one nucleotide is wrong.

    This could result in coding for the wrong amino acid and non-functioning proteins.

  • Q #3: Which of the following answers shows CH4 +2O2=CO2 +H2O as balanced?

    A. CH4 + 2O2 = 2CO2 + 2H2O

    B. 2CH4 + 4O2 = 2CO2 + H2O

    C. 2CH4 + O2 = 2CO2 + H2O

    D. CH4 + 2O2 = CO2 + 2H2O

    Answer Explanation

    For the formula CH4 + 2O2 = CO2 + H2O to be balanced there must be an equal number of molecules on both the reactant and product sides. In this case, for the formula to be balanced, a coefficient of a 2 needs to be placed in front of the O2 and the H2O molecules. This would make both the reactant and product sides have one carbon, four hydrogens, and four oxygens