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A person weighed themselves at 120 lb. Three months later they weighed themselves at 160 lb. Which of the following is the percent of weight the person gained over 3 months? (Round to the nearest percent.)

A. 66%

B. 33%

C. 35%

D. 30%

Answer Explanation:

We need to find the percent change in weight of a person. To find the percent change, follow the following steps:

  • Find absolute change in weight
  • Find relative change
  • Find the percent change from relative change.

 Absolute change is the difference between the final value and initial value. Our initial value is 120 lb and final value is 160 lb. Then,

Relative change is given by

Percent change is determined by

To the nearest whole number, the percent change is 33%.

Therefore, the Correct Answer is B.

More Questions on TEAS 7 Math

  • Q #1: (frac{[2 (8 + 2 * 6)]}{(16 div 2)} = frac{40}{8} = 5) Simplify the expression above. Which of the following is correct?

    A. 6

    B. 2

    C. 5

    D. 3

    Answer Explanation

    We follow the order of operations to solve the given expression.

    First, we start with the numerator and solve

    [2(8+2*6)]

    We start with multiplication in inner brackets, 2*6=12. The expression becomes

    [2(8+12)]

    Then, we conduct the addition of 8+12=20. Then, the expression yields

    [2(20)] = 2*20 = 40

    Now, we solve for denominator, which is 16/2=8.

    Thus, the expression is reduced into

    (frac{[2 (8 + 2 * 6)]}{(16 div 2)} = frac{40}{8} = 5)

    The expression reduces into 5.

  • Q #2: Joe’s uncle is eight less than four times Joe’s age. Which of the equations represents Joe’s uncle’s age (u) as it relates to Joe’s age (k)?

    A. u=8-4k

    B. k=4u-8

    C. k=8-4u

    D. u=4k-8

    Answer Explanation

    We are asked to form an equation to find Joe’s uncle’s age to the age of Joe.

    First, we find Joe’s age which is k. We know that Joe’s uncle’s age is four times that of Joe less 8. Then,

    Joe’s uncle’s age, u = 4k-8.

    Thus, the age of Joe’s uncle is u=4k-8.

  • Q #3: A child has a bottle full of pennies, nickels, dimes, and quarters. There are four as many quarters as pennies, three times as many as nickels as pennies, and five times as many dimes as nickels. How many more dimes does the child have than pennies?

    A. 5 times as many

    B. 10 times as many

    C. 20 times as many

    D. 15 times as many

    Answer Explanation

    Explanation:

    In this question, we need to find the ratio of dimes to quarters.

    If we let x be number of pennies in the bottle. Then,

    Number of quarters in the bottle = 4x

    Number of nickels in the bottle = 3x

    Number of dimes in the bottle =5(3x)=15x

    Now relating dimes to quarters, we have

    Thus, there are 15 times as many dimes as pennies in the box.