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A circle has an area of 121π in2. Which of the following is the circumference of the circle in terms of pi (π)?

A. 11 π in

B. 22 π in

C. 44 π in

D. 5.5 π in

Answer Explanation:

To solve this problem, first find the radius of the circle.

Therefore, the Correct Answer is B.

More Questions on TEAS 7 Math

  • Q #1: A sweater that normally sells for $78 is marked 15% off. Which of the following estimates the sale price of the sweater?

    A. $12

    B. $66

    C. $22

    D. $69

    Answer Explanation

     we are to find the selling price of the sweater from the marked price and the discount. The marked price is given as

    Discount=mark off rate*original price

    Discount=15%*$78

    Convert 15% into a fraction, which become 15/100=0.15. Then

    Discount=0.15*$78=$11.70

    The selling price of the sweater will be the original price less the discount or mark off value. Then,

    Thus, the approximate selling price of the sweater is $66.

  • Q #2: 3(2x+5)=11x+5 Solve the equation above for x. Which of the following is correct?

    A. 1

    B. 2

    C. -1

    D. -2

    Answer Explanation

    We follow the order operations to solve for the unknown value of x.

    3(2x+5)=11x+5

    Open the bracket on the LHS by multiplying each term by 3

    (3*2x)+(3*5)=11x+5

    6x+15=11x+5

    Subtract 15 from both sides

    6x+15-15=11x+5-15

    6x=11x-10

    Subtract 11x on both sides

    6x-11x=11x-11x-10

    -5x=-10

    Divide both sides by -5

    -5x/-5=-10/-5

    x= 2

    Thus, the value of unknown value of x is 2.

  • Q #3: A student performs the following estimations. 26+180210 115+391510 497+20242520 Based on these estimations, which of the following is the student’s estimate of 545+7501?

    A. 8030

    B. 8060

    C. 8160

    D. 8050

    Answer Explanation

    From the given estimations, we can find the exact sum after adding the given numbers and see the trend the student utilizes to find their estimates. The actual sum is as follows

    26+180=206

    115+391=506

    497+2024=2521

    From the above evaluation, the students round the exact sum to the nearest tens. So, in the problem we need to approximate 545+7501.

    545+7501=8046

    The exact sum is 8046 and the approximate value after rounding to the nearest tens is 8050.